In an effort to try and revive some of these literary forums here is a new riddle:
A woman shoots her husband. Then she holds him under water for over 5 minutes. Finally, she hangs him. But 5 minutes later they both go out together and enjoy a wonderful dinner together. How can this be?
From: Upstate NY | Registered: Nov 2001
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Mith - With your permission - I will post a riddle if you dont have any right now.. Bilbo gave Red Caps and Green Caps to the 144 guests (He didnt count how many Red, how many Green, just totalling 144) - he invited in the Party Tent and told them : "Free wonderful Gifts to all of you, if all of you assemble outside in a line with Red Caps on one side and Green caps on the other. No Gifts, if you 'Communicate' to each other!". Ofcourse it was dark in the Tent and nobody could know which was the colour of their own caps. Still the Shrewd "Gross" achieved it, and collected their gifts. How did they do it?
PS: They couldnt see the colour of the caps when they put it on - and arent allowed to remove it after they put it on and went out.
People slot themselves into the line one at a time. So long as there is only one colour of hat in the line, they join an end. As soon as there are two colours already present, they join at the dividing point. Then given that the two colours were properly separated before hand they still will be.
My only worry with this is that organising themselves to join one at a time doesn't sound very hobbit-like (especially at a big party like that!), so this would almost certainly need some communication. But realistically I just don't think they'd manage it if left to their own devices. It should be noted that even the joining the line at the right point and getting people to budge up to make room involves a certain amount of implicit communication.
From: Taruithorn | Registered: Oct 2000
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Fangorn, the last one just go in between the two hobbits with different hats that are together... The solution works, you may have another though.
From: Europe | Registered: Aug 2003
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My Solution is not much different from Laur's. However I am trying to make two lines, Laur made it into a single line. I realized this is because of the way I asked the Question - hence I didnt raise objection to that.
1. All hobbits Queue up one bye one. 2. Number1 stands in a random spot. Number2 joins behind him. 3. Number 3 joins 1&2 if they are both of same colour. If they are not, he stalls. Number2 understands the stall and starts a new line. Number3 joins behind him. 4. After two lines are formed if any line has differing colour at the end, then the next hobbit doesnt join the line - but stalls - so that that error is rectified. So on. 4. The last person stands in a seperate spot. The Hobbits in the line with same colour as him Queue up behind him.
This is my solution - however I am trying to find any alternative solutions on the web - but without much success.